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(1.01^(x^2))'The calculation above is a derivative of the function f (x)
1.01^(x^2)*((x^2)'*ln(1.01)+(x^2*(1.01)')/1.01)
1.01^(x^2)*((x^2)'*ln(1.01)+(x^2*0)/1.01)
1.01^(x^2)*(2*x^(2-1)*ln(1.01)+(x^2*0)/1.01)
1.01^(x^2)*(2*x*ln(1.01)+(x^2*0)/1.01)
1.01^(2*x^(2-1))
0^(x^2)
2*ln(1.01)*x*1.01^(x^2)
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